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Forum CopilulMeu • View topic - Matematica clasa a -2-a

Matematica clasa a -2-a

Micul scolar si problematica adaptarii la noile solicitari! Relatiile familiale si integrarea sociala!

Matematica clasa a -2-a

Postby roxy&alex » Mon Feb 02, 2009 6:30 pm

1)Pisicile dorm cam 16 ore din 24 . Noaptea dorm cu 2 ore mai mult decat ziua.
Cate ore dorm pisicile ziua si cate noaptea?



2)Intr-o familie sunt 3 baieti, fiecare avand o sora.
Cate persoane sunt in acea familie, in care tatal lucreaza in strainatate?


nu stiu! [:D]

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Postby roxy&alex » Mon Feb 02, 2009 8:57 pm

nu stie nimeni?!?!?!?! [plang] [plang]

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Postby Arheoloaga » Mon Feb 02, 2009 9:07 pm

Pai fiind o problema de casa a doua, banuiesc ca trebuie sa foloseasca metoda segmentelor(pe care eu mi-o amintesc foarte vag)...Adica, se ia un segment si se imparte in 16 parti. Stim ca doua segmente din cele 16 se duc la categoria "noapte" si deci, segmentul cel mare ramane format din 14 parti. Aceste 14 parti le impartim la 2 (adica la zi si la noapte). Ne raman doua segmente formate din 7 parti, plus 2 scazute anterior de la segmentul cel mare (16 parti). Rezultatul va fi: pisica doarme 7 ore ziua si 9 ore noaptea.
16-2=14
14/2=7
7+2=9
Dar sunt sigura ca nu au facut impartirea la clasa a doua asa ca trebuie sa foloseasca cel mai probabil metoda segmentelor.

A doua problema e un mister...cred ca ai omis ceva!
Fiecare primeşte un nume când se naşte, dar trebuie să fie în stare să-şi boteze viaţa cu un cuvânt care să-i dea un sens.
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Postby roxy&alex » Mon Feb 02, 2009 10:13 pm

da , e adevarat ,nu au facut impartirea, asa m-am gandit si eu, dar problema este cum sa o desfasoare pe caiet [czid] se duce cu ea nefacuta , o sa o ajute doamna [bis]

multumesc mult Arheoloaga [bis]

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Postby roxy&alex » Mon Feb 02, 2009 10:17 pm

A doua problema e un mister...cred ca ai omis ceva![/quote]


este exact ce era in carte, nici mai mult nici mai putin , cu asta ne luptam zi de zi [czid] [czid] iar cateodata o dam in bara [alc]

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Postby Arheoloaga » Tue Feb 03, 2009 1:36 pm

Hai ca "m-am prins" si de cealalta problema! Acest tip de exercitii face foarte bine mintii la 7/8 ani cat au copiii in clasa a doua...numai ca pt adulti(care au o minte analitica) pot constitui o problema tocmai prin simplitatea lor!
Asadar: 3+3=6 (am adunat numarul copiilor)
6+2=8(am adaugat numarul parintilor)
8-1=7 (am scazut tatal care e in strainatate si am obtinut numarul total de membrii ai familiei).
Repet; poate vei fi surprinsa, insa, daca nu il influentezi pe copil la teme cu ideile tale sau stiu eu ce metode de rezolvare, el va rezolva singur pana la urma. Materia este gandita pentru un anumit stadiu de dezvoltare a mintii...si in plus fiindu-le explicat deja la scoala un anume tip de rezolvare, risti sa creezi confuzie in mintea copilului, care nu mai intelege cum trebuie sa faca: asa cum spune mama sau asa cum explica doamna?
Fiecare primeşte un nume când se naşte, dar trebuie să fie în stare să-şi boteze viaţa cu un cuvânt care să-i dea un sens.
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Postby Arheoloaga » Tue Feb 03, 2009 2:17 pm

Hai ca eu ma laud ca e simpla si eu o dau cu bata in balta.
Copiii sunt 4 (3 baieti care au o sora). Deci 3+1=4
4+2=6
6-1=5 (total membrii)
[noroc]
Fiecare primeşte un nume când se naşte, dar trebuie să fie în stare să-şi boteze viaţa cu un cuvânt care să-i dea un sens.
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Postby roxy&alex » Tue Feb 03, 2009 5:20 pm

[:D] A doua este corecta . Sunt niste probleme dintr-o carte pentru un concurs,si cate unele sunt chiar [czid] este adevarat ,nu stiu eu sa-i explic acasa cum o face doamna la scoala ,eu o ajut foaret putin ,ideile vin de la ea , eu doar ii confirm daca este bine sau nu ,o ajut foarte rar si cateodata [alc] dar se rezolva [bis]
Am fost atenta la lectii din clasa 1 a ca de nu [czid]

Multumesc mult

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Postby roxy&alex » Tue Feb 10, 2009 1:40 pm

compara numerele formate din trei cifre identice cu numarul cu 1 mai mic decat cel alcatuit din 10 sute, apoi ordoneaza-le crescator pe toate in acelasi sir.

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Postby MihaelaStoiciuc » Tue Feb 10, 2009 7:39 pm

nr format din 10 sute din care scadem 1 este un nr de patru cifre, din care ultimele sunt zerouri, deci daca scadem o unitate obtinem un numar de trei cifre egale 999. Acesta este cel mai mare, iar ordinea e urmatoarea:
111 222 333 444 555 666 777 888 999
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